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Topic: Equilibrium and Colours  (Read 2865 times)

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Offline s3a

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Equilibrium and Colours
« on: April 14, 2009, 11:33:20 PM »
In this question, my teacher wrote that the concentration of product increases but isn't it actually the concentration of REACTANT DECREASING?

Answer he gave us:
"With H+ present, OH will be neutralized into H20. Essentially, we now have increased [product]. In this case, the reverse reaction will be favoured.

SOLUTION IS MORE ORANGE."

Offline nj_bartel

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Re: Equilibrium and Colours
« Reply #1 on: April 14, 2009, 11:46:01 PM »
Consider LeChatlier's Principle.  What's disappearing initially?  What's increasing?  In what direction will this drive the reaction?

Offline Borek

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Re: Equilibrium and Colours
« Reply #2 on: April 15, 2009, 03:08:39 AM »
Think in terms of

2CrO42- + 2H+ <-> Cr2O72- + H2O
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Offline s3a

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Re: Equilibrium and Colours
« Reply #3 on: April 15, 2009, 07:25:24 AM »
Oh wait I think I got it! So, if H20 was not on the product side of the reversible equilibrium then I could state that reactant concentration is decreasing instead of product concentration increasing?

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