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Topic: Mole fraction of a tin alloy  (Read 10387 times)

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bonz061583

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Mole fraction of a tin alloy
« on: May 20, 2005, 05:02:47 PM »
The problem states, that given 100 gram block of bronze with heat capacity 27.9 J/K, it asks to calculate the mole fraction of tin in the bronze alloy. It also gives the Dulong-Petit constant = 24.94 J/K*mol, I'm kind of lost on how to start the problem.  ???

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Re:Mole fraction of a tin alloy
« Reply #1 on: May 20, 2005, 05:39:15 PM »
Using D-P constant calculate heat capacity of the pure tin and pure copper (use molar masses). Assume linear dependence between heat capacity and molar fraction.
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bonz061583

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Re:Mole fraction of a tin alloy
« Reply #2 on: May 20, 2005, 07:38:48 PM »
Well I found the heat capacity of tin is .210 J/K*g and that of copper is .392 J/K*g. I just can't figure out what exactly u need to do after that

Offline xiankai

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Re:Mole fraction of a tin alloy
« Reply #3 on: May 21, 2005, 08:09:19 AM »
i heard that alloys do not have a definite melting/boiling point. will this also translate into non-definite heating curves? it doesnt seem to be so in this case, so i am asking now
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Re:Mole fraction of a tin alloy
« Reply #4 on: May 21, 2005, 09:01:51 AM »
Well I found the heat capacity of tin is .210 J/K*g and that of copper is .392 J/K*g. I just can't figure out what exactly u need to do after that

Assume that heat capacity is additive and can be caculated as linear combination of heat capacities of solid components. In case of most metal alloys it holds precisely enough.
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bonz061583

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Re:Mole fraction of a tin alloy
« Reply #5 on: May 22, 2005, 10:51:02 AM »
how exactly do you use the 27.9 J/K heat capacity of bronze, and equat those with the heat capacity of tin and copper?

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Re:Mole fraction of a tin alloy
« Reply #6 on: May 22, 2005, 12:34:58 PM »
x - molar fraction of tin

heat capacity of bronze = x * het capacity of tin + (1-x) * heat capacity of copper.

For most alloys this approach is precise enough, it doesn't mean it can be safely used always.
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bonz061583

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Re:Mole fraction of a tin alloy
« Reply #7 on: May 22, 2005, 04:59:34 PM »
my answer came out to be .379, i'm wondering if that is logically correct, given a 100 g block of bronze.

bonz061583

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Re:Mole fraction of a tin alloy
« Reply #8 on: May 22, 2005, 05:04:41 PM »
actually to correct that, i got x = 0.621

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Re:Mole fraction of a tin alloy
« Reply #9 on: May 22, 2005, 05:08:58 PM »
I would say every answer between 0 and 1 is logically correct when it comes to molar fractions ;)
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bonz061583

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Re:Mole fraction of a tin alloy
« Reply #10 on: May 22, 2005, 05:11:48 PM »
i put in, .621 and it said i was wrong, maybe someone can verify me

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Re:Mole fraction of a tin alloy
« Reply #11 on: May 22, 2005, 05:43:41 PM »
Seems to me you are wrong, show your calculations so that we will be able to look for your mistake.

But I just come with different, probably much easier approach to the problem. First - DP constants is nothing else than a specific heat of one mole of metal. If 100 g of alloy has specific heat of 27.9 J/K there is 27.9/24.94=1.119 mole of metal in the 100 g of alloy.

If tin molar fraction is x and there is a total of 1.119 mole of both metals, mass of the alloy can be expressed as

1.119*x*118.71 (mass of tin) + 1.119 * (1-x) * 63.55 (mass of copper) = 100

Solve for x.
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bonz061583

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Re:Mole fraction of a tin alloy
« Reply #12 on: May 22, 2005, 05:55:50 PM »
 :D Thanks a lot Borek, i appreciate your help, and I don't think this will be the last time i need it.

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