June 26, 2024, 10:25:36 AM
Forum Rules: Read This Before Posting


Topic: Higher Bond order = Shorter Bond...why?  (Read 6025 times)

0 Members and 1 Guest are viewing this topic.

Offline harkkam

  • Regular Member
  • ***
  • Posts: 18
  • Mole Snacks: +0/-0
Higher Bond order = Shorter Bond...why?
« on: May 04, 2009, 03:31:39 AM »
I was reading that a higher bond order makes that bond shorter. That a double bond will be shorter than a single bond.

But why does the extra pair of electrons that is shared in C=C vs a C-C move the carbon molecules together.

Wouldn't the presence of more electrons in the same space produce a repulsion effect or does the nucleus of each atom try and move closer to the extra electron it gets due to a second bond that forms. It has to be to overcome the repulsion of the electrons.

Offline sanderol

  • Regular Member
  • ***
  • Posts: 41
  • Mole Snacks: +2/-1
Re: Higher Bond order = Shorter Bond...why?
« Reply #1 on: May 04, 2009, 03:51:42 AM »
Wouldn't the presence of more electrons in the same space produce a repulsion effect or does the nucleus of each atom try and move closer to the extra electron it gets due to a second bond that forms. It has to be to overcome the repulsion of the electrons.

Molecules form since the attraction(nuclei-electron) overcomes the repulsion (electron-electron + nuclei-nuclei). This fact can be applied to double bonds as well, but now there is more electron density so this means more attraction making the bond shorter/stronger.
When the nuclei will be put closer together the repulsive forces will eventually become more important.

Sponsored Links