[Kalibasa]

Hello I know how to calculate the pH of solutions, any kind, when it deals with protons, but I'm stumped by this scenario. I need to find the pH of a 0.055 M solution of AlCl3. I know it is acidic because of the Al 3+ ion, and I'm guessing this has to do with Lewis acids and bases, but I just can't figure it out! If you could just give me the equation at equilibrium, that alone would help and I could do the rest.

Thanks, I really appreciate it!

[Borek]

Hydrolysis.

[BluRay]

Al³⁺ + nH2O <--> Al(OH)_n + nH3O⁺  ; 1<=n<=3 and n depends on solution's pH.

[AWK]

http://books.google.com/books?id=JoNUVLrNg14C&pg=PA24&lpg=PA24&dq=Al(H2O)6+pKa&source=bl&ots=hFF8ZiR_ec&sig=2YpePYLGaeGP2XT-d0AfDP826v8&hl=pl&ei=h30RSqGaFYu4-Qaeq-jWAw&sa=X&oi=book_result&ct=result&resnum=1

[Kalibasa]

Thank you!