2 Na + 2 HCl ==> 2 NaCl + H2
1g 1.5859g 2.5423g 0.0438g <= results ?1.5859g/L of HCl
Procedure:
Na => 22.98977 * 2 = 45.97954
Cl => 35.453 * 2 = 70.906
H => 1.0079 * 2 = 2.0158
45.97954 + (2.0158 + 70.906) ==> (45.9754 + 70.906) + 2.0158
(72.9218) (116.8814)
Dividing all amounts by the amount of Sodium, I obtained the results under the formula.
Is this a valid procedure?