The equation for another reaction used in industry is:
CO(g) + H2O(g) H2(g) + CO2(g) DHÓ¨ = -42 kJ
2.0 mol of carbon monoxide and 3.2 mol of steam were left to reach equilibrium. At equilibrium, 1.6 mol of both hydrogen and carbon dioxide were present.
I've worked out already that Kc for this reaction is 4.00 and im sure that its correct so here's the question:
Under the same conditions of temperature and pressure, 2.0 mol of carbon monoxide and 2.0 mol of steam were left to reach equilibrium.
Calculate the amounts of each reactant and product at equilibrium.
hmm i dont know what to do because i dont have the equilibrium concentrations of CO and H2O and i only have Kc
Thankyou !!