Hi guys,
Sorry if this is a really elementary question, but I would like some clarification because I don't feel that I completely understand this.
Methylene (CH2) exists in one of two ways; spin paired, or spin unpaired.
I must predict which type of hybridization the carbon adopts.
For spin paired, the two non-bonding electrons must be in the same orbital to be spin paired, so I assumed correctly that the hybridization would be sp2. My question here is why would it form this way with an empty p orbital? do hybridized orbitals always fill before the non-hybridized orbitals do?
For spin unpaired, the answer is sp, leaving two sp orbitals each bonded to a hydrogen 180 degrees apart, and two p orbitals each with one of the two non-bonding electrons. Why wouldn't it be sp3? Do hybridized orbitals only form if there are enough electrons around to fill them?
Thanks!