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Topic: How much rotational energy in a diatomic molecule?  (Read 3007 times)

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Offline oscillate_wildly

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How much rotational energy in a diatomic molecule?
« on: August 05, 2009, 10:57:01 AM »
How much rotational energy would you expect one mole of a diatomic molecule to
possess on average at a temperature T?

I thought the answer would be (1/2RT) x 2 but the question is 3 marks so it can't be. Any help will be greatly appreciated.

Thanks.

Offline Yggdrasil

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Re: How much rotational energy in a diatomic molecule?
« Reply #1 on: August 05, 2009, 12:31:58 PM »
You have the right idea.  From the equipartition theorem, we know that each degree of freedom contributes on average (1/2)RT of kinetic energy per mole [not 1/(2RT) as you have written].  Since linear molecules have only 2 rotational degrees of freedom, the rotational energy would be 2 * (1/2)RT = RT.

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