Wow, I forgot about this site. Sorry if you've given up on me!
I'm still willing to help if I can.
Do you know the heat of reaction? If so, you can find the heat of formation of Cu(OH)2 using this equation:
heat of reaction = (heat of formation of Cu(OH)2 + (Hf NO3-)X2) - (Hf Cu2+ + (Hf OH-)X2).
notice, you don't even have to bother with the Na, because it is the same on both sides of the equation, and therefore will cancel out.