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Topic: Theorteical yield of cc generted per gram of sodium bicarbonate  (Read 5594 times)

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Offline ucrgolfer14

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How do you figure out the cc generated per gram of citric acid or sodium bicarbonate

So far i have
the balanced equation
3NaHCO3 + C6H8O7  :rarrow: Na3C6H5O7 + 3CO2 +3H2O

Then if i have 0.6 g NaHCO3 x [1 mol NaHCO3/ 84.0 g NaHCO3) x (3 mol CO2/3 mol NaHCO3) x (44 g CO2/ 1 mol CO2)

this gives .314 g CO2

Then i convert g CO2 to Liters of CO2 using ideal gas law and get .314 g CO2 x (1 mol CO2/.0071 g CO2) = 44.2 mol CO2

Then ideal gas law using V= nRT/P
i got 1078.2L CO2 produced from 0.6 g NaHCO2 to start with.  What did i do wrong?
This cant be right


Offline sjb

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #1 on: July 15, 2009, 02:27:30 PM »
How do you figure out the cc generated per gram of citric acid or sodium bicarbonate

So far i have
the balanced equation
3NaHCO3 + C6H8O7  :rarrow: Na3C6H5O7 + 3CO2 +3H2O

Then if i have 0.6 g NaHCO3 x [1 mol NaHCO3/ 84.0 g NaHCO3) x (3 mol CO2/3 mol NaHCO3) x (44 g CO2/ 1 mol CO2)

this gives .314 g CO2

Then i convert g CO2 to Liters of CO2 using ideal gas law and get .314 g CO2 x (1 mol CO2/.0071 g CO2) = 44.2 mol CO2

Then ideal gas law using V= nRT/P
i got 1078.2L CO2 produced from 0.6 g NaHCO2 to start with.  What did i do wrong?
This cant be right

0.314g of carbon dioxide is how many moles?

Offline ucrgolfer14

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #2 on: July 15, 2009, 02:30:57 PM »
44.2 mol.  i wrote that in there

Offline sjb

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #3 on: July 15, 2009, 03:18:05 PM »
44.2 mol.  i wrote that in there


No. What is the definition of relative molecular mass?

Offline ucrgolfer14

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #4 on: July 15, 2009, 04:11:31 PM »
i dont understand what you are asking?  i just calculated the moles of CO2 from 0.314 g produced from teh equation.  I think it is 44.2.  I just calculated again and wouldnt i actually go
0.314 g CO2 x 1 mol CO2/ 44 g CO2.  the answer to that is 13.82 mol.  Is that what i did wrong.
I still get 337 L CO2 produced and then caluclating that to ml i get 337000 ml.  or 337000 cc of CO2?  what am i missing.  I think the answer should be around 170 cc?

Offline Borek

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #5 on: July 15, 2009, 04:31:22 PM »
0.314 g CO2 x 1 mol CO2/ 44 g CO2.  the answer to that is 13.82 mol.

No, 0.314/44 is not 13.82.
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Offline ucrgolfer14

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #6 on: July 15, 2009, 04:42:58 PM »
wow.  :-[ ok so it is .0071, then plugging that into the ideal gas law gives .173 L produced then converting that to ml gives 173 ml produced.  and isnt 173 ml equivalent to 173 cc?

Offline Borek

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #7 on: July 15, 2009, 04:47:37 PM »
cc stands for cubic centimeter - and is considered equal to mL.

Historically it wasn't always identical.
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Offline ucrgolfer14

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Re: Theorteical yield of cc generted per gram of sodium bicarbonate
« Reply #8 on: July 15, 2009, 04:51:28 PM »
ok so i have another question??? if you are mixing citric acid an sodium bicarbonate in a 40/60 ratio.  couldnt you theorteically figure out how much CO2 was generated from the citric, and how does the equaation account for mixingthe 2 together because ou cant get the CO2 without adding citric too.  How do you figure out how much citric is needed to generate that amount of cc of CO2?
Sorry was that complicated?

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