Topic: pressure to condense (Read 14296 times)

Ice-cream · « **on:** May 30, 2005, 06:36:52 AM »

can any1 give me some help on this question:

What pressure would have to be applied to steam at 300 degrees C to condense it into liquid water (delta H(vap) = 40.7 kJ/mol)?

Ans. 97.6 atm

I really have no idea wat to do, i can't even start it!! i don't even know which formulae would be used...any1 got any ideas?

Grafter · « **Reply #1 on:** May 30, 2005, 12:23:44 PM »

You need to take the clasius clapyron equation, and take it from there.
use the fact that at boiling point, the pressure of the vapor is 1 atmosphere.

Grafter

ksr985 · « **Reply #2 on:** May 30, 2005, 04:13:55 PM »

If i remember correctly, i answered one of your earlier questions using the clausius clapeyron eqn. Very similar question.

Grafter · « **Reply #3 on:** May 30, 2005, 04:31:31 PM »

Just looked back - yes, very similar question.

Ice-cream · « **Reply #4 on:** May 31, 2005, 10:45:27 AM »

ahhhh ic ic, thanks guys

Donaldson Tan · « **Reply #5 on:** June 04, 2005, 09:12:32 PM »

the clausius-clayperon equation contains the perfect gas assumption, which is normally valid below 5bars. Personally, I prefer a more real answer, so I would look up the steam table (ie. Thermodynamic and Transport Properrties of Fluids by GFC Rogers & YR Mayhew)

Quote

P1 = 85bar, Ts1 = 299.2C
P2 = 90bar, Ts2 = 303.3C
(Ts: Saturated Temperature)

a more real value for the required pressure can be extracted by interpolation of the above data:

P = P1 + (300-299.2)/(303.3-299.2) x (P2 - P1) = 85.97 ~ 86bar

I wouldn't treat steam as a perfect gas because water is polar molecule that exhibits hydrogen bonding. moreover, the required pressure to condense steam at 300K is clearly above 5bars.

ksr985 · « **Reply #6 on:** June 05, 2005, 01:35:15 PM »

pretty good. i thought of the table, but couldnt lay my hands on it. this will, of course, give a more accurate answer.