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Topic: Organic chem. NMR spectra  (Read 11691 times)

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Offline mmohs2

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Organic chem. NMR spectra
« on: September 06, 2009, 03:07:44 PM »
The 1H NMR spectrum of a compound with molecular formula C6H12O is shown here. Draw its structure. 

http://aceorganic.pearsoncmg.com/epoch-plugin/tempfiles/1864_441.jpg
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Offline Borek

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Re: Organic chem. NMR spectra
« Reply #1 on: September 06, 2009, 03:08:41 PM »
Please read forum rules.

You have to show your attempts to receive help. This is a forum policy.
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Offline mmohs2

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Re: Organic chem. NMR spectra
« Reply #2 on: September 06, 2009, 03:13:47 PM »
the degrees of unsaturation=1 and there are only two types of protons. The problem Im having is drawing the structure correctly according to the two singlets. Thanx a lot.
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Offline Borek

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Re: Organic chem. NMR spectra
« Reply #3 on: September 06, 2009, 03:17:25 PM »
Singlets are a very strong hint, but check what is protons ratio first.
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Offline mmohs2

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Re: Organic chem. NMR spectra
« Reply #4 on: September 06, 2009, 03:21:07 PM »
having singlets simply means there are no adjacent protons to split each other's signals.
can u be a bit more helpful?
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Offline Borek

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Re: Organic chem. NMR spectra
« Reply #5 on: September 06, 2009, 03:39:18 PM »
Not many structures that fit such description. Proton ratio makes number of these structures even lower.
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Offline mmohs2

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Re: Organic chem. NMR spectra
« Reply #6 on: September 06, 2009, 03:40:41 PM »
1:3
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Offline Borek

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Re: Organic chem. NMR spectra
« Reply #7 on: September 06, 2009, 05:40:23 PM »
That means 9 protons and 3 protons - two separated structures.
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Offline mmohs2

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Re: Organic chem. NMR spectra
« Reply #8 on: September 06, 2009, 05:49:26 PM »
oh ok I figured it out. it is ch3c=oc(ch3)3

Thanx
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