Hi all,
I'm trying to figure out the geometry of N(CH3)3.First of all, when I have been asked to describe the geometry of N(CH3)3, do I need to analyse each "central atom"? In this case N and the 3 C-atoms, or just the N-atom?.
I have drawn Lewis-structure and of course the Nitrogen atom has one lone pair and 3 bonding pairs of electrons. This would give a tetrahedral, but since the lone pair is "invisible", this is really a trigonal pyramid. Is this correct? Also, the lone pair causes the angle between the C-bondings to be slightly less than 109.5 degrees, right?