Determine the [glu] of the 3 samples using the beer lambert eq. e= 6.22E3
remember to take into account the dilution of each original aliquot into the total assay volume.
Tube unknown(ul) water(ul) glucose(ul) Absorbance
1 0 530 500 0.0
2 30 500 500 0.620
3 30 500 500 0.614
4 30 500 500 0.619
ok i know the beer lambert law
A=e c l converts to c= A/e l
for tube 2 i plugged in my values
C= 0.620/6.22E3*1 = 9.97E-5 M
So i dont understand how to take into account the dilution of the sample to come up with the final answer?
Help PLEASE