[ILoveISO]

1. How would the percent of salt be affected if it were not completely dried at the end?
2. How would the percent of sand be affected if it were not completely dried at the end?

What's the role of Silver Nitrate in this experiment?

And

If excessive splattering and spitting occurred during the heating process of the salt how would the percent of it be affected??

Thanks

[Dan]

At least tell us what the experiment is, we're chemists not psychics...

[JGK]

can't tell, I left my



and



at home this morning

[renge ishyo]

we're chemists not psychics...

Ha! I knew you were going to say that...

[ILoveISO]

it's a seperation of mixtures experiment... I have to separate salt from the sand mixture using filtration

[renge ishyo]

I forsee that nobody will reply because you still haven't provided us with adequate information.

[ILoveISO]

It's basically this lab:

http://www.frapanthers.com/teachers/neblettd/Chemistry/Labs/Chem-Lab%201-Mixture%20Separation.pdf

[ILoveISO]

I don't get how to answer these two questions based on the lab link I just posted:

1. How would the percentage of sand be affected if there were to be excessive splattering/spitting during the heating process of salt?

2. How would the percent of sand be affected if the filtrate was not tested with silver nitrate?

[renge ishyo]

Okie dokie, I'll bite.

From the first post, if you do not allow your isolated compounds to completely dry at the end then when you weigh them your weight will be high because you will be weighing the water along with your compound. I forsee that this will give you higher weights than what you actually have.

I did not see silver nitrate mentioned in the cards or the PDF that you linked to. It is commonly used in older chem analysis methods as a way of measuring the amount of chloride in solution as it precipitates out of water as silver chloride, but I doubt that it is being used that way here. I see that it is being used to "test" for the presence of salt in the water filtrate. In doing so it will use up some of your salt in the test, and so you will get a smaller percentage of salt in your final answer...which means a higher percentage of sand will be calculated. Of course if you didn't use the silver nitrate to test then this wouldn't be the case.

You should avoid splattering of the water solution. It is divined that it will also lead to loss of product as the salt that is in the water will be caught in the splatter and lost leading to a smaller measurement of salt in the end. So it is written.

[ILoveISO]

Thanks renge for the reply I have a couple questions

1. When I use silver nitrate to test the presence of salt, the % you say will go down but how come the % of sand will increase? Does % of salt+% of sand = 100% that's why?

2. How will the % of sand be affected if there's splattering during the heating process of salt? Will it increase as well due to reason above?

[renge ishyo]

I think you are answering your own questions there