January 10, 2025, 05:09:18 PM
Forum Rules: Read This Before Posting


Topic: Calculate the equilibrium constant  (Read 3368 times)

0 Members and 1 Guest are viewing this topic.

Offline Shaun1979

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-0
Calculate the equilibrium constant
« on: October 12, 2009, 02:08:26 PM »
Given [H2] = 0.0343 M, [I2] = 0.326 M, and [HI] = 0.826 M for the following
reaction at 440oC. Calculate the equilibrium constant.
I2 (g) + H2 (g) → HI (g)


I am trying to complete this question as part of revision for up and coming exams.

Is the answer:

[0.826]2/ [0.0343][0.326] = Kc = 61.017 (at 440oC)

correct?

Offline LoveInQuanta

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-0
  • Gender: Female
Re: Calculate the equilibrium constant
« Reply #1 on: October 12, 2009, 02:33:54 PM »
Hey Hey, Shaun,

is the coefficient of HI in the equation actually 2, and you just failed to type it in? If so, your equation is correct, and if not, then you should remove the squaring of the [HI] in the numerator.

Your math is right, if indeed the equation is

I2 (g) + H2 (g) -> 2HI (g)

:)

Offline Shaun1979

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-0
Re: Calculate the equilibrium constant
« Reply #2 on: October 12, 2009, 02:47:47 PM »
Thanks for your reply.

I thought that in order to balance the equation, I would need to add the coeficient 2?

Hmmmmmm, by not placing the coefficient there, how can the equation be in a state of equilibrium?


Offline LoveInQuanta

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-0
  • Gender: Female
Re: Calculate the equilibrium constant
« Reply #3 on: October 12, 2009, 02:54:29 PM »
You do need to add the coefficient 2. But you just didn't type it, so I was making sure that that's what you meant ;)

Offline Shaun1979

  • Regular Member
  • ***
  • Posts: 12
  • Mole Snacks: +0/-0
Re: Calculate the equilibrium constant
« Reply #4 on: October 12, 2009, 03:04:51 PM »
Sorry, chemistry confuses me at the best of times!

That is how they asked the question (without squaring HI), and then I went ahead and squared it when doing Kc, in order to balance it (otherwise it makes no sense).

So I am assuming that I was right in doing so, and that's what you mean?

Sponsored Links