I'm trying to find the :delta: H sol. I want to make sure that I'm on the right path.
moles of NaoH = 0.080
Mass of NaOH =3.1777g
Initial temp = 29.3
final temp 27.5
water = 4.06 J
I used this equation 1st to find the dissolving NAOH
q dissolving NaOH = -mass sol*Csol* :delta:Tsol
q= -3.1777g*4.06J*3.6
= 46KJ
Then I did
q dissolving NaOH/#moles NAOH
46KJ/0.080 =575 J/molNaOH