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Topic: SN2 reaction  (Read 7293 times)

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Offline mandy9008

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SN2 reaction
« on: October 19, 2009, 11:08:29 AM »
I have to draw the major product for this SN2 reaction.
i am not even sure where to begin.
any help will be appreciated. thanks
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Offline nj_bartel

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Re: SN2 reaction
« Reply #1 on: October 19, 2009, 11:20:06 AM »
What is your nucleophile and what is your substrate?
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Offline mandy9008

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Re: SN2 reaction
« Reply #2 on: October 20, 2009, 06:04:58 PM »
i know that the nucleophile attacks the electrophilic carbon (on the substrate) and forces the leaving group to leave, i am just not sure which is which
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Offline craken66

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Re: SN2 reaction
« Reply #3 on: October 20, 2009, 08:50:49 PM »
You have 3 substances: Ethyl chloride, Sodium ethanoxide, Ethanol.
Negative-charged oxygen (-OCH2CH3) of sodium ethanoxide must attack alpha-carbon, that is a carbon atom next to Cl, of ethyl chloride in the ethanol as solvent.
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Offline Xenophilius

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Re: SN2 reaction
« Reply #4 on: October 24, 2009, 06:54:13 AM »
The attacking group is CH3CH2O- and it displaces Cl- from the compound. Cl- being a good leaving group cleaves immediately. The substrate also undegoes Walden Inversion. The product being CH3CH2OCH2CH3, i.e. ethoxy ethane.Alcohol acts as a non-polar solvent.
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XENOPHILIUS....

Offline nj_bartel

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Re: SN2 reaction
« Reply #5 on: October 24, 2009, 10:36:49 AM »
you mean polar protic
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Offline darkness1102

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Re: SN2 reaction
« Reply #6 on: October 24, 2009, 11:49:12 PM »
The SN2 reaction and E2 reation sometime make you wrong. This reaction can make di ethyl ether or propene,depend on your catalysis.
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