There's a picture of Compound B. It's C9H12O3, cyclic, with three carbonyl groups at 1, 4, and 7 positions. I dunno what its called, but i would guess something like cyclonon-1,4,7-trione?
Anyway the question says:
"Compound B was reduced with sodium borohydride (NaBH4). The student used 1.1015g of the molecule. She prepared the sodium borohydride solution by dissolving 1.0085g of sodium borohydride in sufficient solvent to prepare 17.00mL of solution. Calculate the volume of the sodium borohydride solution required to reduce Compound B."
I don't know where to go with this question....All I've done so far is gotten the molar mass of compound B and the number of moles used of everything. And I know that to reduce the compound, you would only need one molecule of NaBH4 per molecule of compound B because its (NaBH4) got 4 H's and there are only 3 carbonyl groups on the compound.
My calculations:
Molar mass of comp. B: 168.186 g/mol
Molar mass of NaBH4: 37.83 g/mol
Moles used of comp. B: 0.00655 moles
Moles used of NaBH4: 0.0267 moles
There is about 4X more NaBH4 than Comp. B.
Where do I go with this??? And how to I incorporate the volume (17mL) to find the answer?
Thanks