December 22, 2024, 06:17:04 PM
Forum Rules: Read This Before Posting


Topic: Reducible representation of Oh Cube, mildly urgent  (Read 5930 times)

0 Members and 1 Guest are viewing this topic.

Offline Enantiomer

  • Regular Member
  • ***
  • Posts: 29
  • Mole Snacks: +2/-0
Reducible representation of Oh Cube, mildly urgent
« on: October 26, 2009, 10:45:58 PM »
Hi folks,
I'm currently racking my brain trying to figure out a question that just doesn't really seem possible to me...
"Consider a metal atom surrounded by a cube-shaped arrangement of eight ligand atoms (Oh symmetry) and derive the reducible representation for the 8 sigma bonds."

Now I've looked up and down and I can't think of a way to get the reducible form of this compound without the irreducible parts to it, regardless I basically just poked around until one worked but I'm basically just short of certain that it isn't right... 
Oh|E  8C3  6C2  6C4  3C42  i  6S4  8S6  3σh  6σd   (where h = 48)
Γ | 8   2      0     0     0    8     0     2     0      0
This works but I'm borderline certain that it isn't right, I've asked freaking everyone about this and they don't seem to know, does anyone have ANY idea what I can do to make a correct reducible compound?

Sponsored Links