[Beachgirl]

I was wondering if Im solving these problems correctly?

1) A sealed container of xeon gas has a temp of 24.3 C at a pressure of 12.0atm. If the container is heated so the new pressure of the gas is 34.6atm, what is the new temperature of xenon gas?

Tinitial = 24.3 C
Pinitial = 12.0atm
pfinal 34.6 atm
? Tfinal 


(Pinitial)(Vinitial)/(Ninitial)(Tinitial)=(Pfinal)(Vfinal)/(Nfinal Tfinal)

I decided that N remains constant and V so I ended up with the equation

(Pi)/(Ti) =(Pf)/(Tf)

which gave me

Tf = Pi/Ti

so

Tf = [(12.0 atm) / (297 kelvin) ] (34.6 atm) = 1.39 Kelvin or
271 Celcius

Is this correct because this gives me a rais in temp of  246.7 degrees and that seems like allot.



#2  A sample of neon gas has a volume of 12.0L at a temp of 55.5 C. If the gas is allowed to expand at a constant pressure such that the new volume of the gas is 28.2L what is the new temp of the gas?

Vi =12.0L
Ti= 55.5 C = 328 Kelvin
Pi = constant

Vf= 28.2L
Pf= constant
T f ?

Vi/Ti = Vf /Tf

so I get

Tf = (Vi/Ti )(Vf)

12.0L/55.5C = 28.2L/Tf

Tf = 12.0L/55.5C (28.2L) = 6.09 C

Is the temperature lowering because the gass molecules are further appart and they creat less net energy so with less energy you have a lowerd temp?

#3 A container of Argon gas has a pressure of 2.29  atm and a Volume of 12.0L. If the volume is increased 51.7L at constant temp, what is the new pressure of the gass?

Well if the volume increases then the preasure should decrease. In the following I just feel like I have to much of a pressure decrease.

Pi=2.29 atm
Vi= 12.0L
Vf=51.7 L
Pf?

(Pi)(Vi)/Vf = (2.29 atm)(12.0L)/51.7L = .532 atm

Am I leaving something out?

#4 A sample od dinitrogen monoxide has  a pressure of 550.7 torr and a volume of 30.2 ml at a temp of 29.6 C If the pressure of the sample is increased to 612.1 torr while holding the temp fixed, what is the new volume of the sample?

Must I convert torrs to atms and Celcius to Kelvin and ml to Liters for this equation to work or will it work just as well if Im lazy and work as is. Oh and to convert torrs to  atm do I divide torr by 760? and to convert ml to liter do I divide ml by 1000?

Well anyhow the following equation is

Boyal = (Pf)(Vf)= (Pi)(Vi)

Pi = 550.7 torr
Vi = 30.3 ml
Ti = 29. 6 C

Tf = 29.6 c
Pf = 612.1 torr
Vf ?

Vf = (550.7 torr)( 30.2ml)/( 612.1 torr) = 27.17 ml

see here my volume came out to be less so dont know ifI did this correctly?

Thankyou for you help and time .

[Borek]

I decided that N remains constant and V so I ended up with the equation

(Pi)/(Ti) =(Pf)/(Tf)

OK

which gave me

Tf = Pi/Ti

?

Tf = [(12.0 atm) / (297 kelvin) ] (34.6 atm) = 1.39 Kelvin or
271 Celcius

No

Approach and general idea are OK, just math is completely messed up.