Let's try this again. Your analysis is correct. The resonance structures can be two aromatic systems, a cyclopropenyl cation and a cyclopentadienyl anion. In that case, why would protonation occur on the cyclopentadienyl cation? Draw the result of the protonation product from C-4. Is it aromatic, non-aromatic, or antiaromatic?
If the cyclopentadiene is more electron rich from electron donation of the cyclopropenyl methylene group, on which carbon will protonation occur? Try each of the carbons, 1, 2, and 3, and determine which carbocation is more stable? Interestingly for me, I thought it was going to be C-3.