[fishyfisherman77]

In this problem-                        Br
                                                        |
H3C-C=CH     +   2 HBr   --->      H3C-C-CH3
                                                        |
                                                       Br

The triple bond goes away why?

& This problem-                 

                                           Br
                                           |
H3C-C=CH      +  HBr ---> H3C-C=CH2
         






why/how does the triple bond go to double bond?



( THE RED BONDS ARE TRIPLE BONDS )

[DrCMS]

because it reacts with the HBr.

[fishyfisherman77]

so with 2 halogens it always goes from triple to single


and hydrogen and halogen it always goes triple to double?
im so cofnsuded

[sjb]

so with 2 halogens it always goes from triple to single


and hydrogen and halogen it always goes triple to double?
im so cofnsuded

Not necessarily. With two equivalents of Br₂ you'd get triple to single, just as with one equivalent of HBr you'd go from triple to double, or double to single.

[fishyfisherman77]

thanks people like  u make this stuff easy )