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Topic: Valance electrons of transition metals  (Read 2849 times)

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Offline Moz

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Valance electrons of transition metals
« on: November 19, 2009, 12:14:13 AM »
How do i find the number of valance elections of a transition metal? My book says that vanadium has 5 valance e-. I thought that valance e- are e- in the highest energy shell, so shouldnt it just be the two electrons in the 4s orbital?

Why does the electron configuration of Ag have only one electron in the 5s shell?

Offline pear

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Re: Valance electrons of transition metals
« Reply #1 on: November 19, 2009, 12:34:26 AM »
If you look at the electron configuration, the charge of a transition metal is the number of electrons in the s & d orbitals after the noble gas core; Vd, for example, is [Ar]3d34s2; 3+2 = 5.  For Ag, even though there are "technically" 11, Gen Chem only requires your understanding that there is 1 in the outermost, unfilled shells.

Offline Moz

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Re: Valance electrons of transition metals
« Reply #2 on: November 19, 2009, 12:55:47 AM »
i understand now, thanks.

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