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Topic: constant (Read 2557 times)
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kapital
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Posts: 197
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constant
«
on:
November 21, 2009, 10:16:12 AM »
Calculate the constant for reaction, between 1 mol ethanol and 1 mol acetic acid, the catalyst h2so4 is present, the reaction yields 2/3 mol ethyl acetate.
My try: Kc=(products)/(reactants)=(0,6666666)/(1*1)=0,666, but it wrong, Why?
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orgoclear
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Re: constant
«
Reply #1 on:
November 21, 2009, 10:51:54 AM »
ethanol + acetic acid --> ethyl acetate + water
t=0 1 1 0 0
t=teq 1/3 1/3 2/3 2/3
Keq = [water][ethyl acetate]/[ethanol][acetic acid]
as all volume terms cancel out concentration can be replaced by no. of moles
so, Keq = 2/3*2/3/(1/3)(1/3) = 4
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constant