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Topic: spin of electron  (Read 2174 times)

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Offline faith

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spin of electron
« on: November 26, 2009, 06:14:34 PM »
Prove that [√ n+ (n+2)] = 2√s(s+1) where √ is the square root of spin of electron
µS0 = 2SMB
Where µS0 = magnetic motion of spin electron
S= spin electron
MB= Bohr magnetron
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