Oh alright.
Well the reaction goes to completion because its a strong base, so the OH- concentration will also be 1.2 x 10-7 M. But you also need to account for the self dissociation of water, which will make it 2.2e-7.
Then, -log(2.2e-7) = pOH = 6.6575
14-6.6575 = 7.3424, which should be pH.
Anyone know what i did wrong?