[tdean]

I have .5 mole solution of Ag(NO3) but its in limited supply. I only need a .1 m solution. Is it possible to dilute the .5 mole solution to make a .1 mole? I'd say I have about 100 mL of .5 mole. Is it as simple as adding 400 mL of water to 100 mL of .5 mole solution?

0.1 mole => 16.988 g
16.988 g + enough water to reach the volume of 1 L

0.5 mole => 84.935 g
84.935 g + enough water to reach the volume of 1 L

Also, I'm looking to make an aqueous solution of copper II nitrate to observe single replacement reactions of zinc and of iron.
What concentration of copper II nitrate would work best? What ratio of copper II nitrate crystals to water do I use to make that soltution?
Will the reactions work with Zinc dust rather than zinc wire? and iron fillings rather than iron wire?

[Borek]

http://www.chembuddy.com/?left=concentration&right=dilution-mixing