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Topic: Ka vs temperature  (Read 7278 times)

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Offline vhpk

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Ka vs temperature
« on: March 07, 2010, 10:05:09 AM »
I have a question from my textbook regarding the temperature and Ka.
The Ka of CH3COOH and CF3COOH are 4.75 and 0.23 respectively, and nearly independent of temperature. Suggest reason for this?
I really have no idea for this question? Can you help me with this?
Thank you
Genius is a long patience

Offline renge ishyo

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Re: Ka vs temperature
« Reply #1 on: March 07, 2010, 01:15:56 PM »
The equation for the temperature dependence of an equilibrium constant is given by the Van T' Hoff equation (source: http://en.wikipedia.org/wiki/Equilibrium_constant):

d(ln[Keq])/dT =  :delta: H/RT2

If the change in the enthalpy (:delta: H) is very small then you would predict that the change in the equilibrium constant will also be small. :delta: H happens to be very small for acetic acid at -0.41 kJ mol-1 (source: http://en.wikipedia.org/wiki/Acid_dissociation_constant ; scroll down to the thermodynamics table to compare this value to other acids in the table).

Offline vhpk

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Re: Ka vs temperature
« Reply #2 on: March 08, 2010, 10:54:15 AM »
Thank you for the reply :)
Genius is a long patience

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