January 15, 2025, 04:44:01 PM
Forum Rules: Read This Before Posting


Topic: E1 / ring strain  (Read 2911 times)

0 Members and 1 Guest are viewing this topic.

Offline viet

  • Regular Member
  • ***
  • Posts: 34
  • Mole Snacks: +0/-2
E1 / ring strain
« on: March 08, 2010, 03:45:16 PM »
i'm suppose to draw 2 major products from:
1-(3-methylcyclobutyl)ethanol  + (H2SO4 + heat). I don't understand how the ring-expanding rearrangement come into play with carbonation intermediates.

Offline honeyissticky

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Re: E1 / ring strain
« Reply #1 on: March 08, 2010, 05:23:16 PM »
you could use this rationale to make sense of why some rings will undergo ring expansion:

We know that a cyclpentane would love to expand to a cyclohexane, because of relieved ring strain. Therefore, we can expect a ring expansion to be favorable to to a hydride shift in this case. Try applying this to your question. Would a cyclopropane do the same? What about a cyclobutane/heptane?


Sponsored Links