[bamster]

We did a lab where we recovered cyclohexene from cyclohexanol using distillation. We started with 16.7 ml of cyclohexanol and retrieved 5.5 ml of cyclohexene at the end. It says to calculate the percent yield of it. The problem is is that it gives the theoretical yield in grams. We used volume because we didn't have solid cyclohexanol, but it says in the beginning steps to use either 16g, 16.7 ml or 0.16 mols of cyclohexanol. Basically, i know that the reaction between cyclohexene and cyclohexanol is a 1:1 mol ratio. But i don't understand how to get 5.5 ml of cyclohexene and convert it to mols? In the lab manual, the theoretical yield is 8-9 g. So for the 8-9g ill pick 8.5g, ill take the 8.5 g and divide by the molar mass of of cyclohexene (82) to get the moles of theoretical.

I don't have the concentration of cyclohexanol we used so i don't really know how to get the 5.5 ml into moles.
 Wait: i forgot it gave the specific gravity of something as 0.96 g/ml. would i use that.
5.5ml / 0.96 = 5.7 mols

lol or its 5.5 ml x 0.96 = 5.28 g
5.28 g / 82.14 g/mol = 0.06 mols

[Borek]

Volume times specific gravity is mass.

[Smrt guy]

Specific gravity is not the same as density, which I think is what you meant there.  If you need the density go to aldrich.com

[Borek]

Specific gravity is not the same as density

Technically you are right, for all practical purposes they have identical values, differences start at about 4th or 5th significant digit.

That is assuming it is measured against water, not some other liquid