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Topic: Reversible Reaction Problem  (Read 3492 times)

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Offline Pitseleh

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Reversible Reaction Problem
« on: May 06, 2010, 06:38:05 PM »
Hi, I hope someone can be of help. I'm confused about this question and hope someone can shed some light on it... Or me. Thanks!

Which of the following listed below will shift the equilibrium to the LEFT for the following reversible reaction?

SrCO3(s) <----> Sr2+(aq) + CO32-(aq)

a) decrease Sr2+
b) increase CO32-
c) add solid SrCO3
d) add solid NaNO3
e) all of the above
« Last Edit: May 06, 2010, 06:40:04 PM by Borek »

Offline Borek

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Re: Reversible Reaction Problem
« Reply #1 on: May 06, 2010, 06:40:56 PM »
Use sub/sup buttons in editor to format your formulas.

Please read forum rules.

Do you know LeChatelier's principle?
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Offline Pitseleh

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Re: Reversible Reaction Problem
« Reply #2 on: May 06, 2010, 06:44:58 PM »
No, I just know the law of chemical equilibrium. I'm confused. C seems to only make sense, but my friends tell me it's an increase in CO3

Offline Borek

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Re: Reversible Reaction Problem
« Reply #3 on: May 07, 2010, 03:01:19 AM »
Le Chatelier's principle is related to equilbirium, see

http://en.wikipedia.org/wiki/Le_chatelier's_principle

Your friend is right.
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