[GWashington1732]

I need to calculate the equivalent weight and normality of Na₂C₂O₄

I have the amount of grams per liter= 6.6783 g/l
I have the equation= H₂C₂O₄-----> 2CO₂+ 2H⁺ + 2e^-
I have the amount of solution used= 25.0 ml= .025 l
But I have no idea what I need to do with this information.

[AWK]

Could you calculate molarity of this solution?

http://en.wikipedia.org/wiki/Concentration#Normality

[GWashington1732]

Could you calculate molarity of this solution?

http://en.wikipedia.org/wiki/Concentration#Normality

I got .049 M for the molarity.

From the link, how are gram equivalents calculated?

[GWashington1732]

I figured it out. The equivalent weight was the molar mass divided by 2 and the Normality was the grams per liter divided  by the equivalent weight. Which is exactly what I came up with the first time I tried it.
This was just a case of, it was too simple, so therefore, it must be hard. 

[Thujone]

I figured it out. The equivalent weight was the molar mass divided by 2 and the Normality was the grams per liter divided  by the equivalent weight. Which is exactly what I came up with the first time I tried it.
This was just a case of, it was too simple, so therefore, it must be hard. 

Normality means equivalents per liter, equivalents in this case meaning H+ given off.  Na2CO4 doesn't give off any protons, which makes it 0 Normal, regardless of it's molarity.

[Borek]

Normality means equivalents per liter, equivalents in this case meaning H+ given off.  Na2CO4 doesn't give off any protons, which makes it 0 Normal, regardless of it's molarity.

You are not only using narrow definition of normality, you are also using it wrong. C₂O₄^2- accepts two protons, which makes normality of the solution equal twice its molarity.