[h1234]

my lecturer solved this got answer but i got different answer can you check who got the right answer

my lecturer

Example to show the relationship between Eoand Eo:NAD+(aq) + H+(aq) + 2e---> NADH Eo= -0.11 V (assume a = c)
Ee= Eo–RT lncproductssame as: Ee= Eo–RT lnQ
nFcreactantsnF
where Q = cNADH= 1
cH+. CNAD+cH+. 1(All species except H+are in their standard concs.)
Eo= Eo+ (RT/2F) lncH+= Eo+ (RT/2F) x2.303 xlog10H+
= -0.11 –0.02957 pH= -0.11 V –0.2957 x7 = -0.32 V


my answer is 0.0969 v

who is right?
but i dot