September 16, 2024, 03:25:55 PM
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Topic: Given volumes in neutralization, how do I find the concentration of an acid?  (Read 6155 times)

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Offline Rhydos

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What is the concentration of acetic acid in vinegar when 32.5 ml of 0.56M Ca(OH)2 are required to neutralize 15 ml of the vinegar?

How would I go about solving this?  What steps would I have to use?

Offline Jorriss

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If it's a neutralization reaction, we know moles of base = moles of acid at the end right? And is there any way to solve for either moles of acid or moles of base?

Offline Borek

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Offline Schrödinger

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If it's a neutralization reaction, we know moles of base = moles of acid at the end right?
I don't think that's correct.

It is always true that equivalents of acid = equivalents of base. Moles can be equated only if the acidity of the base and the basicity of the acid are the same. examples : NaOH and HCl, Ca(OH)2 and H2SO4,etc
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Offline Reckoner

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Find the number of moles of base.

How many moles of OH- are in 1 mole of Ca(OH)2? How many moles of H+ in 1 mole of ethanoic acid? Neutralisation is when the moles of H+ = moles of OH-. Hence you can find the number of moles of acid, and then the concentration in vinegar.

Offline aeacfm

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i think that the determination  must be in moles not in equivalents

Offline Borek

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i think that the determination  must be in moles not in equivalents

Determination must be in moles, but they react in equivalents - so you have to account for the difference.
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Offline aeacfm

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good catch thank you

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