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Topic: Can someone check to see if I solved this pH prob. correctly?  (Read 2256 times)

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Offline rubystar91

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Can someone check to see if I solved this pH prob. correctly?
« on: July 08, 2010, 01:45:37 PM »
If 22.5 mL of 1.4x10-4 M HI is added to 28.0 mL of 4.4x10-3 M HI, what is the pH of the solution?

Do I solve it this way?
1.4x10-4+4.4x10-3= 4.54x10-3 M HI
22.5mL+28.0mL=50.5mL=.0505L
4.54x10-3/.0505=0.089901
pH=log(0.089901)=1.05

Is that correct?

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Offline sjb

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Re: Can someone check to see if I solved this pH prob. correctly?
« Reply #1 on: July 08, 2010, 01:49:39 PM »
Quote from: rubystar91 on July 08, 2010, 01:45:37 PM
If 22.5 mL of 1.4x10-4 M HI is added to 28.0 mL of 4.4x10-3 M HI, what is the pH of the solution?

Do I solve it this way?
1.4x10-4+4.4x10-3= 4.54x10-3 M HI
22.5mL+28.0mL=50.5mL=.0505L
4.54x10-3/.0505=0.089901
pH=log(0.089901)=1.05

Is that correct?



No, I don't believe it is. You can't just add molarities like that.

How many moles of HI are there in your first solution? And in your second? In what total volume?
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