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Topic: Question of Chiral  (Read 4066 times)

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Offline zhouduck

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Question of Chiral
« on: June 25, 2010, 09:59:08 PM »
Is 2-bromobicyclo[2.1.1]hexane chiral? I think is achiral; however my solution says it's chiral.... ???
« Last Edit: June 25, 2010, 10:10:12 PM by zhouduck »

Offline Jorriss

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Re: Question of Chiral
« Reply #1 on: June 25, 2010, 11:10:14 PM »
I'm not sure what direction you name these from, is the bromine on the 1 or 2 carbon side?

Offline zhouduck

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Re: Question of Chiral
« Reply #2 on: June 26, 2010, 01:34:26 AM »
You're right. I should name the cycloalkane from the longest circle according to the IUPAC rules. As a result, it should be chiral. Thank you!

Offline Dan

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Re: Question of Chiral
« Reply #3 on: June 26, 2010, 01:35:03 AM »
It is chiral. Here are a few ways of looking at it:

The carbon bearing the bromine has 4 different substituents, it is an asymmetric centre. It is also the only asymmetric centre, therefore the compound could not be meso and it must be chiral.

The molecule has no plane or centre of symmetry, so it must be chiral.

The mirror images are non-superimposable (make models if necessary), it is chiral
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Offline zhouduck

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Re: Question of Chiral
« Reply #4 on: June 26, 2010, 03:04:56 AM »
Thank you, Dan! :]

Offline mcdonabe

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Re: Question of Chiral
« Reply #5 on: July 12, 2010, 05:33:43 PM »
Easy rule of thumb, if you see a carbon that has four unique substituents (and there are no planes of symmetry) there is chirality

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