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Topic: simple dilution,  (Read 3163 times)

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Offline loaf

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simple dilution,
« on: July 15, 2010, 12:53:47 AM »
hi,
I am diluting for first time, am I correct?

I am using 35% conc Hcl to dilute it so the final pH will be 2 with final quantity 6 ltrs
I tried this way,

density of conc acid=1.18
Molarity= 35x1.18/100 = 11.315 M
pH= -log11.315 = -1.05

final pH=2, Molarity= 10^-2 = .01

M1xV1 = M2xV2
V1= .01 x  6/11.315=5.3 ml Answer



Offline AWK

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Re: simple dilution,
« Reply #1 on: July 15, 2010, 02:42:28 AM »
Molarity= 35x1.18/100 = 11.315 M
Thic calculation accidentally work (error 1.3 % gives you 2 significant digits correctly, but it works only for 35 % HCl) . You should use formula
c=10pd/M (p-percent concentration, d-density in grams/dm3, M - molecular mass of HCl in grams - you may use kilograms instead of grams in both d and M)
AWK

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