[abadir16]

In benzene solution, triethylamine, (C2H5)3N, reacts with bromoethane, C2H5Br, according to the following time-independent stoichiometric equation:

(C2H5)3N + C2H5Br = (C2H5)4N+Br−

If the ratio of the experimental rate constants at 333 K and 320 K (that is,
kR(333 K)/kR(320 K)) is equal to 2.0, use this information to estimate the Arrhenius activation energy for the reaction.       


choices are:

        136 kJ mol−1     
   21 kJ mol−1    
   75 kJ mol−1    
   47 kJ mol−1    
   93 kJ mol−1    

any help is appretiated.

[plankk]

In the Arrhenius equation the preexponential factor is constant for reaction in every temperature. So you should educe the factor A from the Arrhenius equation and equate each other (in both temperatures) and from it find the value of activation energy.

Good luck!

[Dan]

Please do not cross post, see http://www.chemicalforums.com/index.php?topic=42578.0