[NickF.]

hey, this is about the Karl Fischer titration...

i do not know how to start with this excercise. The titer of a karl fischer solution is given in water equivalent( whatever this is) and the numerical value of it is 4.8 mg/ml. Now they take an oil sample of 10 g and the consumption caused by the titration is 1.65ml.
And now the question, what is the mass percentage of water in the oil, that was tested.
Can somebody give me an approach?

Thanks for your *delete me*

[Borek]

If 1 mL of titrant is 4.8 mg of water, and you used 1.65 mL, how many mg of water were present?

[NickF.]

ah, now I got it...thanks