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How much heat is released as the temperature of 25.2 grams of iron is decreased from 72.1C to 9.8C? The specific heat of iron is 0.444J/g(C).

113 J
0 (0%)
566.1 J
0 (0%)
1.11 kJ
0 (0%)
0.697 kJ
0 (0%)
957 J
0 (0%)

Total Members Voted: 0

Voting closed: September 10, 2010, 02:48:55 PM

Topic: chemistry/specific heat  (Read 6353 times)

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Offline klg90

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chemistry/specific heat
« on: September 05, 2010, 02:48:55 PM »
How much heat is released as the temperature of 25.2 grams of iron is decreased from 72.1C to 9.8C? The specific heat of iron is 0.444J/g(C).

Offline klg90

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Re: chemistry/specific heat
« Reply #1 on: September 05, 2010, 02:51:47 PM »
I used the equation for specific heat but I think that answer is for the heat absorbed not released. I'm confused about how to get the heat released.
« Last Edit: September 05, 2010, 03:24:47 PM by klg90 »

Offline Borek

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Re: chemistry/specific heat
« Reply #2 on: September 05, 2010, 03:00:09 PM »
Please read forum rules.

q = m c deltaT
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Offline klg90

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Re: chemistry/specific heat
« Reply #3 on: September 05, 2010, 03:08:56 PM »
I used the equation for specific heat but I think that answer is for the heat absorbed not released. I'm confused about how to get the heat released.

Offline Borek

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Re: chemistry/specific heat
« Reply #4 on: September 05, 2010, 03:39:34 PM »
Sorry, I must have opened the thread before you posted at 20:51:47 missed the post.

Doesn't matter if the heat is absorbed or released, it is the same formula - just opposite sign.
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Offline klg90

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Re: chemistry/specific heat
« Reply #5 on: September 05, 2010, 04:26:43 PM »
I stayed stuck after this step:

100g(TF - 100C)=(200g)(Tf)-20C)

(Tf)=100g(Tf)

Offline Borek

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Re: chemistry/specific heat
« Reply #6 on: September 05, 2010, 05:54:00 PM »
Where did you got 100g and 200g from? Where did you got 100 deg C and 20 deg C from?

I told you explicitly what formula to use.
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