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Topic: Empirical formula?  (Read 4888 times)

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Offline The_Journey

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Empirical formula?
« on: September 12, 2010, 07:11:08 PM »
I'm not asking for answers, I'm asking on what steps should I be using to solve this (apparently) really tough question.

An unknown compound contains Carbon, Hydrogren, and Nitrogen. Upon analysis it is found to contain 60% Carbon. When 4.00-g of the compound is burned, all of the hydrogen is converted to 0.033-moles of water.

a) What is the weight of each element in a 4.00-g sample of the unknown compound?

b) What is the empirical formula?

For a, I converted 0.033-moles of water to 0.594g of water and then found the mass of the Hydrogen, which is 0.066g.
60% of Carbon in a 4.00-g sample means there is 2.4g of Carbon in the sample.
Then for Nitrogen, I subtracted 0.066g and 2.4g from 4.00g to get 1.534g as the mass for Nitrogen

I'm stuck at b, I converted Hydrogen, Carbon, and Nitrogen into moles, which turned out to be 0.2 mol of C, 0.11 mol of N, 0.066 mol of H. Then I tried dividing them all to find the whole number ratios, that is when I got ridiculous numbers for the unknown compound. I think I got like C9H3N5 as the formula for the unknown compound, which is obviously wrong.

Can someone help me to find what I did wrong?

Thank you.

Offline opti384

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Re: Empirical formula?
« Reply #1 on: September 12, 2010, 10:59:06 PM »
I took a glance at your process and it seems fine. I'm not sure what C9H3N5 is, but organic compounds' formulas could look bizarre or C9H3N5 could just be contrived for the problem.

Offline Borek

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