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Topic: Seaborgium  (Read 3466 times)

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Offline oceanmd

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Seaborgium
« on: September 24, 2010, 05:44:24 PM »
When writing the electron configuration for the element Seaborgium, the final electron written enters a(n) (blank) orbital
Choices: s, p, d, f

Electron configuration for Sg is 1s2 2s2p6 3s2p6d10 4s2p6d10f14 5s2p6d10f14 6s2p6d4 7s2

I was absolutely sure about the answer, but when I got my work back is is marked as wrong. My answer was s

Please help. What is the correct answer

Offline MrTeo

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Re: Seaborgium
« Reply #1 on: September 25, 2010, 02:57:58 AM »
First of all you have to consider the increasing energy in the orbitals, not only the increase of the principal quantum number:

http://en.wikipedia.org/wiki/Electron_configuration#Aufbau_principle_and_Madelung_rule

when you've done if still your answer is not right think about the anomalies of the d-block elements in their electron configurations...
The way of the superior man may be compared to what takes place in traveling, when to go to a distance we must first traverse the space that is near, and in ascending a height, when we must begin from the lower ground. (Confucius)

Offline oceanmd

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Re: Seaborgium
« Reply #2 on: September 27, 2010, 06:22:54 PM »
MrTeo,

Thank you. Is is so simple to answer this question and so complicated to understand the whole mechanism behind it.

Thank you again

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