When writing the electron configuration for the element Seaborgium, the final electron written enters a(n) (blank) orbital
Choices: s, p, d, f
Electron configuration for Sg is 1s2 2s2p6 3s2p6d10 4s2p6d10f14 5s2p6d10f14 6s2p6d4 7s2
I was absolutely sure about the answer, but when I got my work back is is marked as wrong. My answer was s
Please help. What is the correct answer