[intellic]

The Q is as follows..
Sodium Carbonate crystals ( 27.8230 g ) were dissolved in water and made up to 1 dm3. 25 cm3 of the solution were neutralized by 48.8cm3 of Hydrochloric Acid of concentration 0.100 mol/dm3. Find 'n' in the formula Na2CO3:nH20

I have no idea how to do this one... I have done the rest of the questions on this worksheet but this one I simply can't solve..I try to construct a balanced equation but without the 'N' It seems futile.. I know there'll be an extra water molecule with n in the complete reaction due to neutralization but still.. am really puzzled!
Anyone helping please give a bit of detail on how you solved the question along with the ans..
Ty in advance.

[Borek]

Can you calculate number of moles of carbonate from amount of hydrochloric acid?

[intellic]

I think they should be half the number of the moles of the HCL. Which comes to 0.00244 moles of the hydrated sodium carbonate.

[Borek]

Can you calculate mass of the sodium carbonate - as if it was anhydrous?

[intellic]

In the data the mass is given of the anhydrous crystals.. yeah..

[Borek]

No, mass is given for carbonate as dissolved - that means hydrated.