Sorry, but I have another one of these H=E+P :delta: V questions
For which exothermic reaction is :delta: E more negative than :delta: H?
A) Br
2(l)
Br
2(g)
B) 2C(s) + O
2(g)
2CO(g)
C) H
2(g) + F
2(g)
2HF(g)
D) 2SO
2 + O
2(g)
2SO
2(g)
My logic is that, if H=E+P :delta: V, and you want :delta: E < :delta: H, then you have :delta: E < :delta: E + P :delta: V and so 0 < P :delta: V. Since P is always positive, then the change in volume must also be positive, and the moles of gas products must be more than the moles of reactants. However, the answer is D, which is just the opposite. Where did I go wrong?