[Skye]

Hey, I have to identify an unknown compound as part of my prac component and I am having a lot of trouble interpreting the NMR.

My H NMR has a singlet at about 9.7 (one contributing H), a doublet at about 7.7 ( 2 contributing H), a doublet at about 6.6 (2 contributing H) and a singlet at about 3.0 (6 contributing H)

My C NMR has peaks at 190, 154, 133, 124, 110 and 40.

As far as I can tell its a para substituted aromatic aldehyde but all the structures I come up with either need an extra H or C to make it fit. eg at first I thought it was isopropylacetophenone but there is not enough H peaks. I think it is the integration of 6 hydrogens at 3 that is causing the confusion, but my integration is exactly 1cm, 2cm, 2cm and 6cm respectively.

I would appreciate any help you could give me

[ironman2538]

Are you sure about the number of carbon atoms in a molecule....  wht all other element does it have... it could simply be N,N-Dimethyl group and you are missing a nitrogen....? that would make it 4-N,N-Dimethylamino benzaldehyde...?? or like tht...

[Skye]

You are a champion, that fits all my other results!!!! We didn't get given the formulation, just the compound (as in the physical chemical) and had to figure the rest out for ourselves and for some reason I completely missed the N. Thankyou!!