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Topic: NADP+ reduction?  (Read 5549 times)

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Offline vanklik

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NADP+ reduction?
« on: October 05, 2010, 05:28:17 PM »
What is the chemical difference between NADP+ and NADPH? What exactly NADP+ accepts when it gets reduced and how many of them?
Thanks!
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Offline JGK

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Re: NADP+ reduction?
« Reply #1 on: October 05, 2010, 05:44:15 PM »
Theres this amazing thing called "Google" you know

http://www.bio.davidson.edu/courses/Bio111/NADPH.html
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Offline vanklik

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Re: NADP+ reduction?
« Reply #2 on: October 06, 2010, 02:17:11 AM »
No, I've got no idea about Google. Thanks for telling me!

As to the rest of my question, I would be really greatful if anyone could explain me why after addition of the hydrogen atom the positive charge dissappearing? Doesn't it need 2 electrons and 1 proton to make a molecule neutral? Unfortunately the amazing Google doesn't explain it very well.

Thanks
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Offline JGK

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Re: NADP+ reduction?
« Reply #3 on: October 06, 2010, 03:41:25 PM »
Did you even look at the link I posted!

The bottom part shows the bond changes in the nocitinamde ring structure caused by the addition of the hydrogen and shows the loss of the +ve charge from the N atom in the ring strucure.
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Offline vanklik

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Re: NADP+ reduction?
« Reply #4 on: October 06, 2010, 05:28:44 PM »
Yes, I did look at the link and it didn't explain what I was looking for. It's not the hydrogen that is added but hydride ion that has a proton and 2 electrons. If the hydrogen was added (as you are saying) then +ve charge would still be there.

 
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Offline Doc Oc

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Re: NADP+ reduction?
« Reply #5 on: October 06, 2010, 07:01:22 PM »
Quote from: vanklik on October 06, 2010, 05:28:44 PM
It's not the hydrogen that is added but hydride ion that has a proton and 2 electrons.

That's the answer.  Hydrogen isn't added, it's a hydride.
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