reduction:
2H+ + 2 e---> H2 (g); E0 = 0V
Oxidation possibilities:
2 H2O --> 4 H+ + 4 e- + O2 (g); E0 = -1.23V
ro
2Ag(s) + H2O --> Ag2O + 2 H+ + 2 e-; E0 = -1.17V (partial oxidation of silver)
or
Ag (s) --> Ag+ + e-; E0 = -0.80V (full 1-valent oxidation of silver)
which one of the oxidation reactions costs the least energy based on the NERNST equation? This is the one that will happen in electrolysis.