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Topic: Change In Enthalpy, Another Quick Question  (Read 2113 times)

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Offline Boxxxed

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Change In Enthalpy, Another Quick Question
« on: October 16, 2010, 05:27:00 PM »
We have

C + 2H2 + 1/2 O2 ----> CH3OH

The heat of formation value is -201.0 KJ/mol

We want to find the change in enthalpy is 2.4 g of carbon is used

Moles Carbon = 0.1998

0.1998x(-201.0) = -40.2 KJ

Why is the book dividing 201.0 by 0.1998 to get -1006.0 KJ/Mol C?

We are using less carbon so there should be less energy released.

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Offline JustinCh3m

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Re: Change In Enthalpy, Another Quick Question
« Reply #1 on: October 18, 2010, 11:46:18 PM »
what you've done is correct.  Are you using Zumdahl by any chance?  I've found quite a few errors in the Zumdahl text.
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Offline Boxxxed

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Re: Change In Enthalpy, Another Quick Question
« Reply #2 on: October 20, 2010, 09:52:33 AM »
It's a book of walkthroughs through different types of questions. Surviving University by Maria Sokolova
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