What is the solubility of MX3 solid in 0.10 M M(NO3)3?
MX3 M3+ + 3X1- (Ksp = 1.9e-09)
At first I thought that:
M(NO3)3 -> M3+ + 3NO3-
x (0.10 + 3x)
So 1.9E-9 = (x)(0.1)^3, but that was wrong...
Then I thought:
MX3 -> M3+ + 3x-
(0.1 + x) 3x
So 1.9E-9 = (0.1)*(3x)^3, but that was wrong too...